Page 703 - 水土保持手冊_10612

(3)淤滿( H m = 5 . 9 )、最大流量時( h = 0 . 2 m 、 h = . 1 38 m 、 h = 0 . 1 m )
ck
c
A.荷重分析[ H 1 = 0 ； H = m 2 H m tanα = . 1 36 m ； H = h + H = 0 . 2 m ；κ 2 = 1 − (H o ∑b op ) /(BH a ) = .0 744 ]
1
3
2
作用力 符號 計算式 R R 作用點 力矩
h
v
W .0 κ 2 γ c m 1 H a 2 =15.4 +15.4 L − 2 m 1 H a 3 / = 11 2 . 172.5
5
1
壩體自 W κ γ t H = 48.8 + 48.8 m H + t 2 / = 1 . 9 444.1
重 2 2 c 1 a 2 a 1
5
W .0 κ 2 γ c m 2 H a 2 = 61.8 + 61.8 2 m 2 H a 3 / = . 5 07 313.3
3
P wh 1 .0 5γ wc 2 ( h + H 1 )H 1 κ 2 = 0 +0 0
P wh 2 .0 2 [ 5 γ wc H 3 +γ H m ]H m κ 2 = 41.4 +41.4 (H m 3 / )[H m + 3H 3 )] /[H m + 2H 3 )] = 4 . 3 140.8
w
5
P .0 γ wc m 2 H 1 2 =0 + 0 0
wv
1
靜水壓
力 P wv 3 .0 5γ w m 2 H m ( H + H 2 ) = 41 3 . +41.3 m 2 H m 3 / = . 2 53 104.5
m
P wv 4 .0 5γ wc m 2 H m H = 7 . 5 +5.7 2m 2 H m 3 / = . 5 06 28.8
2

P wv 5 5.0 γ wc h ( + h c ) m 2 H = 14 0 . +14.0 m 2 H a 2 / = 8 . 3 53.2
土-4-25
a
P wv 6 .0 5γ wc h ( c + h k t ) 1 = 8 . 4 +4.8 m 2 H a + t 1 2 / = 1 . 9 43.7
5 .
P 0 ×γ sub × K ac × H m 2 = 35 3 .
a
土砂壓 P P 35 cos 66 13 9 . . 3 17
力 ah a cos( + εδ ) = 3 . × 8 . = +13.9 H m 3 / = 44.0
P P a sin( + εδ ) = 35 3 . × sin 66 8 . = 32 4 . +32.4 m 2 H m 3 / = . 3 17 102.7
av
5 .
上揚力 U 0 ×γ w × C × L ( × H + H + h ) = 24 0 . -24.0 L 3 / = 8 . 4 -115.2
m
B
2
合計 200.2 55.0 1332.4