Page 694 - 水土保持手冊_10612

5. 未淤滿( H m = . 8 12 m )、土石流體撞擊、土石流巨礫撞擊( D = 0 . 1 m)
E
(1)荷重分析 ( H = H − H = 5 . 9 − . 8 12 = . 1 38 m； H = m 2 H tanα = . 1 15 m ； H = h + H = . 1 38 m
2
a
m
1
3
1
m
2
q = γ me h DE = . 1 336 × . 0 62 = . 0 83 / t m )
作用力 符號 計算式 R R 作用點 力矩
h
v
5 .
W 0 γ c m 1 H a 2 = 20 . 76 +20.76 L − 2 m 1 H a 3 / = 11 . 23 233.0
1
壩體自重 W γ c t 1 H a = 65 . 55 + 65.55 m 2 H a + t 1 2 / = 1 . 9 596.5
2
5 .
W 0 γ c m 2 H a 2 = 83 0 . + 83.0 2 m 2 H a 3 / = . 5 07 421.0
3

P wh 1 0 γ w H 1 2 = . 0 95 +0.95 H 1 3 / + H m = . 8 58 8.2
5 .
P wh 2 0 γ w 2 ( H 3 + H m )H m = 44 . 17 +44.17 (H m 3 / )(H m + 3H 3 ) /(H m + 2H 3 ) = . 3 05 134.7
5 .

P 1 0 γ m H 2 = . 0 76 +0.76 m H + m H 3 / = . 6 86 5.2
5 .
靜水壓力 wv w 2 1 2 m 2 1

P wv 2 γ w m 2 H m (H 1 − H 2 ) = 5 . 1 +1.5 m 2 H m 2 / = . 3 25 4.9
土-4-15
5 .
P wv 3 0 γ w m 2 H m (H m + H 2 ) = 28 . 45 +28.45 m 2 H m 3 / = . 2 17 61.7
P wv 4 0 γ w m 2 H m H 2 = 1 . 2 +2.1 2m 2 H m 3 / = . 4 34 9.1
5 .
2
P 0 5 . K ac γ sub H m + K ac qH m = 38 8 .
a
土砂壓力 P P a cos( + εδ ) = 19 . 12 +19.12 H m 3 / = 7 . 2 51.6
ah
P P a sin( + εδ ) = 33 . 74 +33.74 m 2 H m 3 / = . 2 17 73.2
av
5 .
上揚力 U 0 γ w C B L H a = 15 2 . -15.2 L 3 / = . 4 17 -68.4
2
土石流體撞擊力 P γ me h DE U DE / g = . 0 78 +0.78 h DE / 2 + H = . 0 62 / 2 + . 8 12 = . 8 43 6.6
f
m
土石流巨礫撞擊力 P 20 2 . U DE 6 5 / D E 2 / B =3.1 +3.1 D E / 2 + H = / 0 . 1 2 + . 8 12 = . 8 62 26.72
m
d
合計 221.0 68.12 1564.32